10a^2-4a+17=10

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Solution for 10a^2-4a+17=10 equation: 



10a^2-4a+17=10

We move all terms to the left:

10a^2-4a+17-(10)=0

We add all the numbers together, and all the variables

10a^2-4a+7=0

a = 10; b = -4; c = +7;
Δ = b2-4ac
Δ = -42-4·10·7
Δ = -264
Delta is less than zero, so there is no solution for the equation

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